The reaction $CH_3CONH_2 \xrightarrow{NaOBr}$ gives:

  • A
    $CH_3Br$
  • B
    $CH_4$
  • C
    $CH_3COBr$
  • D
    $CH_3NH_2$

Explore More

Similar Questions

Which of the following nitrogen compounds gives a primary amine upon reaction with $Br_2$ and strong $KOH$ (Hofmann bromamide degradation reaction)?

What product is obtained by the reduction of $(CH_3)_2C=NOH$ using $Na$ and $EtOH$?

An aromatic compound $A$ having molecular formula $C_7H_6O_2$ on treating with aqueous ammonia and heating forms compound $B$. The compound $B$ on reaction with molecular bromine and potassium hydroxide provides compound $C$ having molecular formula $C_6H_7N$. The structure of $A$ is

The conversion of propan$-1-$ol to $n-$butylamine involves the sequential addition of reagents. The correct sequential order of reagents is:

The conversion of $C_6H_5CONHCH_3$ to $C_6H_5CH_2NHCH_3$ can be carried out by using:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo